Question

plz help me in this maths question of geometry ( similarity) hope you will help me to complete this homework and I will mark you as brainliest​

Answer 1

Step-by-step explanation:

Q2.

For similar triangle,

AB/PQ = A(∆ABC)/A(PQR∆)=4/5

Q3.

Area of triangle= 1/2*height*base

Then,

A1/A2=(1/2*b1*h) / (1/2*b2*h)

[let, two triangle have common height =h]

A1/A2 = b1/b2

b1= (A1/A2)*b2= (3/2)*12 = 18cm