Question

plz help me in this question

Answer 1

Hope it helps....!!!

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SOLUTION:

In ΔABC and ΔCDA,

∠BAC = ∠DCA (Alternate interior angles, as p || q)

AC = CA (Common)

∠BCA = ∠DAC (Alternate interior angles, as l || m)

∴ ΔABC ≅ ΔCDA (By ASA congruence rule)

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Answer 2

In triangle ABC and triangle CDA
AC = AC --- common side
Angle ACB = Angle CAD --- alternate angles
Angle BAC = Angle ACD --- alternate angles
Triangle ABC and CDA are congruent by ASA test