plz help me in this question
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Refer the attachment for figure.
Given when angle is 30°, then height of water is 1 m
Now, tan∅ = P/B
here, in first case ∅ = 30° and P = 1 m
=> tan30° = 1/B
=> 1/√3 = 1/B
=> B = √3
Now base is √3 m
Now, in second case, P = 3m (given)
B = √3 m (derived)
We have to find ∅
So tan∅ = P/B
=> tan∅ = 3/√3
=> tan∅ = (3√3)/3 (by rationalising)
=> tan∅ = √3
But tan60° = √3
=> tan∅ = tan60°
=> ∅ = 60°
Hence, your answer is 60°
Hope it helps dear friend ☺️
Given when angle is 30°, then height of water is 1 m
Now, tan∅ = P/B
here, in first case ∅ = 30° and P = 1 m
=> tan30° = 1/B
=> 1/√3 = 1/B
=> B = √3
Now base is √3 m
Now, in second case, P = 3m (given)
B = √3 m (derived)
We have to find ∅
So tan∅ = P/B
=> tan∅ = 3/√3
=> tan∅ = (3√3)/3 (by rationalising)
=> tan∅ = √3
But tan60° = √3
=> tan∅ = tan60°
=> ∅ = 60°
Hence, your answer is 60°
Hope it helps dear friend ☺️
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