Question

plz..... help me in this question

Answer 1

Answer:

k = ±4

Step-by-step explanation:

Given Quadratic Equation is 3x² - k√3x + 4 = 0

On comparing with ax² + bx + c = 0, we get

a = 3, b = -k√3x, c = 4.

Given that the equation has real roots.

∴ Δ = 0.

⇒ b² - 4ac = 0

⇒ (-k√3)² - 4(3)(4) = 0

⇒ 3k² - 48 = 0

⇒ 3k² = 48

⇒ k² = 48/3

⇒ k² = 16

⇒ k = ±4.

Therefore, the value of k = ±4.

Hope it helps!

Answer 2

hope it helps you bro I try only not bast