Question

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Answer 1

A

It cannot be zero.

B

Its magnitude is greater than the distance travelled by the object.

Displacement:-The shortest distance between initial and final position of the body.

It can be zero and its magnitude is always less than the distance travelled by the object.

Hence, option A and B are not true for displacement.

The correct option is A and B.

Answer 2

Answer:

options (1) and (3)

Explanation:

Given :

A particle is displaced by 4 m East, and then 3 m North.

To find :

the total displacement and distance covered

Solution :

• The displacement is the shortest distance between the initial and final positions of an object. (depends on the path)

And it is a vector quantity as it has both magnitude and direction.

The particle is displaced by 4 m East, and then 3 m North.

So, the displacement vector = $\rm 4 \hat{i}+3\hat{j}$

where

 $\rm \hat{i}$ is the unit vector along x - direction

 $\rm \hat{j}$ is the unit vector along y - direction

Magnitude of displacement

 $\rm = \sqrt{4^2+3^2} \\\\ \rm =\sqrt{16+9} \\\\ \rm =\sqrt{25} \\\\ \rm =5 \ m$

Therefore, the total displacement is 5 m

• The distance is the total length of the path covered by the object and it is independent of path.

So, the distance covered = 4 m + 3 m = 7 m