Plz help me in this question (with steps)
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Hi friend,
=>(√2+√3)/(3√2-2√3)
Rationalising factor = 3√2+2√3
=> (√2+√3)/(3√2-2√3) × (3√2-2√3)/(3√2+2√3)
=>(√2+√3)(3√2+2√3)/(3√2-2√3)/(3√2+2√3)
=>√2(3√2+2√3)+√3(3√2+2√3)/[(3√2)²-(2√3)²]
=>3(2)+2√6+3√6+2(3)/[9(2)-4(3)]
=>6+5√6+6/(18-12)
=> 12+5√6/6
=> 12/6 + 5√6/6
=> 2 + 5√6/6 = a + b√6
By comparing,
a = 2 and b = 5/6
Hope it helps...
=>(√2+√3)/(3√2-2√3)
Rationalising factor = 3√2+2√3
=> (√2+√3)/(3√2-2√3) × (3√2-2√3)/(3√2+2√3)
=>(√2+√3)(3√2+2√3)/(3√2-2√3)/(3√2+2√3)
=>√2(3√2+2√3)+√3(3√2+2√3)/[(3√2)²-(2√3)²]
=>3(2)+2√6+3√6+2(3)/[9(2)-4(3)]
=>6+5√6+6/(18-12)
=> 12+5√6/6
=> 12/6 + 5√6/6
=> 2 + 5√6/6 = a + b√6
By comparing,
a = 2 and b = 5/6
Hope it helps...
SouravBangera1:
thanks
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