Chemistry, asked by ramesh05, 11 months ago

plz help me it's very urgent.

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Answered by Anonymous
19
ANSWER :-

solution

peneplain gives the end point corresponding to the reactions :

NaOH + HCl ------------> Nacl + H2O

Na2CO3 + HCl ---------------> NaHCO3 + NaCl

so,

m- moles of NaOH + m - moles of Na2CO3

= m - moles of HCl = 2.5

methyl orange gives the endpoint corresponding to the reaction :

NaOH + HCl ----------------> Nacl + H2O

Na2CO3 + 2HCl -------------> 2Nacl + CO2 + H2O

so,

m- moles of NaOH + m - moles of Na2CO3 * 2

= m- mole of HCl = 30 * 0.1 = 3


m- moles of Na2CO3 = 0.5

m- moles of NaOH = 2.5 - 0.5 = 2

Ratio of m- moles of NaOH and Na2CO3

= 2/0.5 = 4:1


________________________

❤BE BRAINLY ❤
Answered by bibiborkataki12
1

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bibiborkataki12

Secondary SchoolChemistry 5+3 pts

Plz help me it's very urgent.

Report by Ramesh05 11.10.2018

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bibiborkataki12

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Danevankerk

Danevankerk Emerger Moderator

ANSWER :-

solution

peneplain gives the end point corresponding to the reactions :

NaOH + HCl ------------> Nacl + H2O

Na2CO3 + HCl ---------------> NaHCO3 + NaCl

so,

m- moles of NaOH + m - moles of Na2CO3

= m - moles of HCl = 2.5

methyl orange gives the endpoint corresponding to the reaction :

NaOH + HCl ----------------> Nacl + H2O

Na2CO3 + 2HCl -------------> 2Nacl + CO2 + H2O

so,

m- moles of NaOH + m - moles of Na2CO3 * 2

= m- mole of HCl = 30 * 0.1 = 3

m- moles of Na2CO3 = 0.5

m- moles of NaOH = 2.5 - 0.5 = 2

Ratio of m- moles of NaOH and Na2CO3

= 2/0.5 = 4:1

________________________

❤BE BRAINLY ❤

The life is for chill dude

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