Question

plz help me Mates.......​

Answer 1

Given :–

• A triangular park ABC has sides,

1. 120m
2. 80m
3. 50m  

To Find :–

• Area to be planted.
• Cost of fencing it with barbad wire at the rate of Rs. 20 per meter and leaving a space of 3m wide for gate at the one side.  

Solution :–

First, we need to find to be planted.

Area to be planted =  Where,  Given that,

• a = 50
• b = 80
• c = 120

Now, put the value on it.

⟹ $\dfrac{50 + 80 + 120}{2}$

⟹ $\dfrac{250}{2}$

⟹ 125

• s = 125m

Now, put all the values on the heron's formula.

⟹  $\sqrt{125(125-50)(125-80)(125-120)}$

⟹  $\sqrt{125(75)(45)(5)}$

⟹ $\sqrt{(25 \times 5)(25 \times 3)(9 \times 3)(5)}$

Now, keep the same numbers.

⟹ $\sqrt{(25 \times 25)(5 \times 5)(3 \times 3)(3)(5)}$

Now, turn the same numbers in the front side of the root.

⟹ $25 \times 5 \times 3 \sqrt{3 \times 5}$ 

⟹ $375 \sqrt{15}$

Hence,

Area to be planted = 375√15m²  

Now, we need to find the cost of fencing which is leaving space of 3m wide.

So,

Meters to be fenced = side 1 + side 2 + side 3 – leaving space

• side 1 = 50
• side 2 = 80
• side 3 = 120

⟹ 50 + 80 + 120 – 3

⟹ 130 + 120 – 3

⟹ 250 – 3

⟹ 247

Hence,

Meter to be fence = 247m

Now,

Cost of per meter = Rs. 20 [given]

Cost of fencing a triangular park = Cost of per meter × meter to be fenced

⟹ 20 × 247

⟹ 4940

Hence,

Cost of fencing a triangular park = Rs. 4940

Answers :–

• Area to be planted = 375√15m²
• Cost of fencing a triangular park = Rs. 4940

Answer 2

Answer:

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