Question

plz help me .........
maths ..
solve this ....
question no 1 and 2 and 3 plz plz plz

Answer 1

question no(1):
____________

ratio of their radii r1 : r2 = 2 : 3

ratio of their areas will be

πr1^2 : πr2^2

= (r1)^2 : (r2)^2 = (2)^2 : (3)^2

= 4 : 9

Answer:
_______
ratio of their areas = 4 : 9

question no.(2):
_____________

area of square = 121 cm^2

(side)^2 = 121 => side = 11cm

length of wire used in square (perimeter)

= 4 × side = 4 × 11 = 44cm

since this wire is bent in the form of circle

then ,

length of wire = perimeter of circle

44cm = 2πr

r = 44 × 7 / 44 = 7cm

area enclosed by the circular figure

= πr^2 = 22(7)^2/ 7

= 154cm^2

Answer:
_______
area of circular figure = 154cm^2

question no.(3):
_____________

diameter of circular park

= 35m

radius = 35 ÷ 2 = 17.5m

area of circular park

= πr^2 = 22 × (17.5)^2/ 7

= 962.5m^2

width of flower bed = 1.4m

radius of park including flower bed

R= 17.5 + 1.4 = 18.9m

area of park including flower bed

= πR^2 = 22 × (18.9)^2/ 7

= 1122.66m^2

area of the flower bed

= area of park including flower bed - area of park

= 1122.66 - 962.5 = 160.16m^2

Answer:
_______
area of the flower bed= 160.16m^2