Question

plz help me na



plz solve this question plz​

Answer 1

p^2 + 1/p^2 = 18

Step-by-step explanation:

$p - \frac{1}{p} = 4(given)$

Consider p− 1/p =4, squaring both sides, we get:

$(p - \frac{1}{p} )^{2} = {(4)}^{2}$

${p}^{2} - 2 \times p \times \frac{1}{p} + ( \frac{1}{p} )^{2} = 16$

${p}^{2} + ( \frac{1}{p} )^{2} = 16 + 2$

${p}^{2} + \frac{1}{ {p}^{2} } = 18$

Answer 2

Answer:

18

Step-by-step explanation:

$p-\frac{1}{p} =4\\(p-\frac{1}{p}) ^{2} = 4^{2}$

$(p-\frac{1}{p} )^{2} = 16\\p^{2} +\frac{1}{p^{2} } -2*p*\frac{1}{p} =16\\(using identity (a-b)^{2} = a^{2}-2ab+ b^{2}) \\p^{2} +\frac{1}{p^{2} } -2=16\\p^{2} +\frac{1}{p^{2} } =16+2\\p^{2} +\frac{1}{p^{2} }= 18$

Hope It Helps :)