plz help me out...........
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Step-by-step explanation:
speed of aircraft= x
Distance = 2800 km
Time = Distance / Speed = 2800/x
Given:
The speed has reduced by 100 and time is reduced by 30 min
New speed = (x – 100)
That is, 30 min = 30/60 hr = (1/2) hr
Time taken= 2800/(x – 100) hr
=2800/(x – 100)
= (2800/x) + (1/2)
2800/(x-100) -` (2800/x) = 1/2
x² - 100x - 560000 = 0
x² - 800x + 700x - 560000 = 0
x(x - 800) + 700(x - 800) = 0
(x + 700) (x - 800) = 0
SO,
x = - 700 or 800
Thus original duration of the flight = 2800/800 = 7/2 hours
OR = 3 hr 30 mins
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