Question

plz help me out as it urgent​

Answer 1

$\huge \red{answer}$

$\large \pink{given = {} \large \bf abcd \: is \: parallelogram \: \:}$

$\large \pink {{ \underline{to \: find = }}\bf \large angle \: x \: y \: and \: z}$

$\bf \green{finding \: y \: angle} \\ \bf \green{if \: abcd \: is \: parallelogram \: then \: opposite \: angels \: are \: equal \: } \\ \bf \green{ie \boxed{angle \: a \: = angle \: c \:}{ and} \boxed{ \: angle \: b \: = \: angle \: d \: }}$

$\bf \green{so \: 125 = angle \: c \: where \: angle \: c = y + 56} \\ \bf \green{125 = y + 56} \\ \bf \green{y = 125 - 56} \\ \bf \green{y = 69}$

$\bf \blue{to \: find \: x} \\ \bf \purple{now \: sum \: of \: all \: sides \: of \: parallelogram \: is \: = 360} \\ \bf \purple{ie \: a \: + b \: + c + d = 360} \\ \bf \purple{angle \: a = 125 \: angle \: b = angle \: d \: and \: angle \: c = 125 } \\ \bf \purple{125 + b + 125 + d= 360} \: \: (\purple{angle \: d = x \: then \: b \: = x \: also}) \\ \bf \purple{2 \times 125 + x + x = 360} \\ \bf \purple{2 \times 125 + 2x = 360} \\ \bf \purple{2(125 + x) = 360} \\ \bf \purple{125 + x = 180} \\ \bf \purple{x = 180 - 125} \\ \bf \purple{x = 55}$

$\bf \blue{to \: find \: z} \\ \bf \orange{now \: in \: triangle \: cbe \: angle \: ecb = 56 \: and \: b = 55} \\ \bf \orange{sum \: of \: all \: angels \: of \: triangle = 180} \\ \bf \orange{angles \: ecb + b + bec =180 }$

$\bf \orange{56 + 55 + bec = 180} \\ \bf \orange{111 + bec = 180} \\ \bf \orange{bec = 180 - 111} \\ \bf \orange{ bec= 59} \\ \bf \orange {now \: angle \: e = 180 \: (straight \: angle)} \\ \bf \orange{then \: z + bec = 180} \\ \bf \orange{z + 59 = 180} \\ \bf \orange{z = 180 - 59} \\ \bf \orange{z = 111}$