Question

plz help me out frm this


and no wrong answers and spamming

need content quality answers, ,,,,,

plz answer only of u know

Answer 1

Heya buddy

here your answer goes like this

"""""plz refer the attachments ,,,, for your answer """"""

i hope that it helps you

Answer 2

Hi...✌

Here is your answer...☺

$k = cosec \theta + cot\theta\\ \\ RHS\: \\ = \frac{ {k}^{2} - 1 }{ {k}^{2} + 1 } \\ \\ = \frac{(cosec \theta + cot\theta )^{2} - 1}{(cosec \theta + cot\theta )^{2} + 1} \\ \\ = \frac{cosec ^{2} \theta + cot^{2} \theta + 2cosec \theta \: cot \theta - 1}{cosec ^{2} \theta + cot^{2} \theta + 2cosec \theta \: cot \theta + 1} \\ \\ = \frac{cosec ^{2} \theta - 1 + cot^{2} \theta + 2cosec \theta \: cot \theta}{cosec ^{2} \theta + cot^{2} \theta + 1 + 2cosec \theta \: cot \theta } \\ \\ = \frac{cot ^{2} \theta + cot^{2} \theta + 2cosec \theta \: cot \theta}{cosec ^{2} \theta + cosec^{2} \theta + 2cosec \theta \: cot \theta} \\ \\ = \frac{2cot^{2} \theta + 2cosec \theta \: cot \theta}{2cosec ^{2} \theta + 2cosec \theta \: cot \theta} \\ \\ = \frac{2cot \theta ( cosec \theta + cot \theta)}{2cosec \theta ( cosec \theta + cot \theta)} \\ \\ = \frac{cot \theta}{cosec \theta} = \frac{ \frac{ cos \theta}{sin \theta}}{ \frac{1}{sin \theta} } = cos \theta=\: LHS$

Hence LHS = RHS proved

Thank you ⭐