plz...... help me out guys
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ohh here ur ans on attachment..........
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Step-by-step explanation:we know that the sum of interior angles of a triangle=360^
Also, sinx =cosec(90-x)...(1)
Now sin(b+c/2)=cosec(90-(b+c/2))
Sin(b+c/2)=cosec[180-(b+c)/]
Now a+b+c=180
b+c=180-a
Thus sin(b+c/2)=cosec(180-(180-a)/2)
Sin(b+c/2)=cosec a/2
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