Question

plz help me out with the question no. 8 and 9. this is for class 8th ex : 6.1. plz help me today i have my maths exam so plz help

Answer 1

8. (i) 49 is the square of 7.

Therefore it is the sum of 7 odd numbers.

49 = 1 + 3 + 5 + 7 + 9 + 11 + 13

(ii) 121 is the square of 11.

Therefore it is the sum of 11 odd numbers

121 = 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21

9. How many numbers lie between squares of the following numbers:

(i) 12 and 13

(ii) 25 and 26

(iii) 99 and 100

(i) Since, non-perfect square numbers between n^2 and (n^2)+1 are 2n

Here, n = 12

Therefore, non-perfect square numbers between 12 and 13 = 2n = 2×12 = 24

(ii) Since, non-perfect square numbers between n^2 and (n^2)+1 are 2n

Here, n = 25

Therefore, non-perfect square numbers between 25 and 26 = 2n = 25×2 = 50

(iii) Since, non-perfect square numbers between n^2 and (n^2)+1 are 2n

Here, n = 99

Therefore, non-perfect square numbers between 99 and 100 = 2n = 2×99 = 198

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