Question

plZ help me out write on paper Ans send me a picture OK I will be making u brilliant OK

Answer 1

$\underline\bold{\huge{Good\: Afternoon!!\: :}}$

Let the consecutive numbers.

X,X+1,X+2,

So, According to questions they were Multiply with 2,3,4 respectively.

So, 2X,3(X+1),4(X+2)

And given that their sums is 74

so, 2X+3(X+1)+4(X+2)=74

2X+3X+3+4X+8=74

=>9X+11=74

=>9X=74-11

=>9X=63

=>X=63/9

=>X=7

So, replacing the value we got

7,8,9.

$\underline\bold{So, the\: no's\: are\: 7,8,9\: :}$

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Answer 2

Let the three consecutive multiples of 8 be 8n,8n+8,8n+16

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8n+8n+8+8n+16=888

24n+24=888

24(n+1)=888

n+1=37

n=36

8n=288

8n +8=296

8n+16=304
8n=304-16
8n=288
n=288÷8
n=36
1 no=8×36=288
2 no =8n+8=8×36+8=296
3 no 8n+16=8×36+16=304
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