Question

plz help me over in this que​

Answer 1

Step-by-step explanation:

let four consecutive integer are

x,x+1,x+2,x+3

so,x+x+1+x+2+x+3=178

4x+6=178

4x=172

x=172/4

x=43

Answer 2

Answer:

Let the required integers be x, x+1, x+2 and x+3

According to the given problem, we have

$x + ( x+ 1) + (x + 2) + (x + 3) = 178 \\ x + x + 1 + x + 2 + x + 3 = 178 \\ 4x + 6 = 178 \\ 4x = 178 - 6 \\ 4x = 172 \\ x = \frac{172}{4} \\ \boxed{x = 43}$

• Therefore, the integers are :

1. x = 43
2. (x+1) = 44
3. (x+2) = 45
4. (x+3) = 46