Question

plz help me plz armies don't spam me plz​

Answer 1

IN triangle PQR

sides = PQ , QR , PR

angles = <PQR , < PRQ , < QPR

In triangle XYZ

<Z = 180 - (<X + <Y)

= 180 - (60+30)

= 180 - 90

= 90°

IN triangle MNO ,

<O = 180 - ( <M + <N)

= 180 - (35 + 90 )

= 180 - 125

= 55°