Question

plz help me...


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Answer 1

Answer:

1.) 1

2.) 0

Step-by-step explanation:

1.). Divisibility of 9 = Sum of all digits should be divisible by 9

so,. 2+1+y+5 = y + 8

9 = y + 8

y = 9 - 8

y = 1

ANSWER = 1

2.). Divisibility of 9 = Sum of all digits should be divisible by 9

so,. 3+1+z+5 = z + 9

9 = z + 9

z = 9-9

z = 0

ANSWER = 0

Answer 2

Answer:

$\huge \bold {\mathscr \purple{AnSwEr \: of \: q \: 1}} \\ \: \green{given} \\ \bold{question : 1} \\ If \: 21y5 \: is \: a \: multiple \: of \: 9 , \: where \: y \\ \: is \: a \: digit \: , \: what \: is \: the \: value \: of \: y \: ??\\ \bold{solution} \\ 21y2 \: is \: a \: multiple \: of \: 9 \: \\ \\ \therefore \: 2 + 1 + y + 2 \: is \: a \: multiple \: of \: 9 \: \\ \\ 8 + y \: is \: a \: multiple \: of \: 9 \\ \\ \therefore \: 8 + y = 9 \: ( \: multiple \: of \: 9 \: greater \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: than \: 8 \: and \: nearest \: to \: 8 \: ) \\ \\ \therefore \: y = 9 - 8 \\ \\ = 1 \\ \\ \huge \bold {\mathscr \purple{AnSwEr \: of \: q \: 2}} \\ \: \green{given} \\ \bold{question : 1} \\ If \: 31z5 \: is \: a \: multiple \: of \: 9 \: , \: where \: z \\ \: is \: a \: digit \: , \: what \: is \: the \: value \: of \: \: z \: ?? \\ </p><p>\ \bold{solution} \\31z5 \: is \: a \: multiple \: of \: 9 \\ \\ \therefore \: 3 + 1 + z + 5 \: is \: a \: multiple \: of \: 9 \: \\ \\ 9 + z \: is \: a \: multiple \: of \: 9 \\ \\ \therefore \: 9 + z = 9 \\ \: \: \: \: \: \: \: \: or \\ \: \: \: \: \: \: \: 9 + z = 18 \\ \\ 9 + z = 9 \: or \: 9 + z = 18 \\ z = 9 - 9 \: or \: z = 18 - 9 \\ z = 0 \: \: or \:\: z = 9$

hope it helps u buddy ✌️✌️