Plz help me plz find x from the figure.
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First of all u construct a line AB||CD||EPF
and find by using (co-interrior angles)
/_BOP+/_OPF=180°
100°+/_OPF=180°
/_OPF=80°. -------1
Similarly,find/_FPQ=60°--------2
adding equation 1. +. 2
X=140°
#__kcrys_singh....
and find by using (co-interrior angles)
/_BOP+/_OPF=180°
100°+/_OPF=180°
/_OPF=80°. -------1
Similarly,find/_FPQ=60°--------2
adding equation 1. +. 2
X=140°
#__kcrys_singh....
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∠PCQ = 180 - 120 = 60°
∠PAR = 180 - 100 = 80°
∠R = Q = 90°
∠RPA = 180 - (90 + 80) =180 - 170 = 10°
∠QPC = 180 - (90 + 60) = 180 - 150 = 30°
So ∠APC = X = 180 - (10 + 30) = 180 - 40 = 140°
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