Question

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Answer 1

$\large\underline\purple{\bold{Solution :- }}$

We know,

• Angle opposite to equal sides are always equal.

In triangle ABC

• AB = AC (GIVEN)

• ⇛∠ABC = ∠ACB -------(1)

Also,

In triangle DBC

• DB = DC (GIVEN)

• ⇛ ∠DBC = ∠DCB ---------(2)

On adding (1) and (2), we get

• ∠ABC + ∠DBC = ∠ACB + ∠DCB

• ⇛ ∠ABD = ∠ACD

$\large{\boxed{\boxed{\bf{Hence, Proved}}}}$