Question

plz help me plzplzz​

Answer 1

Answer:

we know that,

according to Newton's third equation of motion;

v^2 = u^2 + 2as

where

v is fine velocity of the body

u is the initial velocity of the body

a is the acceleration

s is the distance covered

in case of free fall;

u=0 {when a body is dropped from a height, the initial velocity is zero}

a= g { acceleration due to gravity}

s = h { given}

thus, putting these values, the equation becomes;

v^2 = 0^2 + 2gh

v^2 = 2gh

v=√(2gh)

hence derived