Question

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Answer 1

this is the answer of your question

Answer 2

ANSWER

${x}^{2} + \frac{1}{ {x}^{2} } = 7 \\ \\ {x}^{2} + \frac{1}{ {x}^{2} } = 9 - 2 \times x \times \frac{1}{x} \\ \\ {x}^{2} + \frac{1}{ {x}^{2} } + 2(x)( \frac{1}{x} ) = 9 \\ \\ ( {x + \frac{1}{x} })^{2} = 9 \\ \\ x + \frac{1}{x} = + 3............eq(1) \\ \\ because \: it \: is \: given \: not \: to \: take \\ negative \: ans \: of \: x + \frac{1}{x} \\ \\ take \: cube \: on \: both \: side \: of \: eq(1) \\ ({x + \frac{1}{x} })^{3} = 27 \\ \\ {x}^{3} + \frac{1}{ {x}^{3} } + 3(x)( \frac{1}{x} )(1 + \frac{1}{x} ) = 27 \\ \\ {x}^{3} + \frac{1}{ {x}^{3} } + 3(3) = 27 \\ \\ {x}^{3} + \frac{1}{ {x}^{3} } = 18...... |answer|$