plz help me question no 10
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AthiraUday123:
I think the answer is root 7 sin^2 theta - sin^2 theta
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cot theta = √7
so, tan theta = 1/√7
we know, cosec² theta = 1 + cot² theta
sec² theta = 1 + tan² theta
so, in place of cosec² theta and sec² theta , we will put cot² theta and tan² theta. after simplifying, we will get the answer as 2400.
hope this helps you.
so, tan theta = 1/√7
we know, cosec² theta = 1 + cot² theta
sec² theta = 1 + tan² theta
so, in place of cosec² theta and sec² theta , we will put cot² theta and tan² theta. after simplifying, we will get the answer as 2400.
hope this helps you.
yeah bye work hard
it will be. we are the 1st batch to give boards with the whole syllabus after a long time.
bye. same to you
hmm
answer is not 240 i think
sry, 2400 it is. u will get numerator 48/7 and denominator 50/7. so, it will be 48×50 = 2400
i had forgotten to add that 0 in the last
no it will be 48/50
ek min..
oh no! bas ek silly mistake. haan, wahi hoga jo tumne bola. thank you, meri inhi galtiyon ki wajah se exam me marks kat jate hai
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cot theta =V7 so,tertheta =1/7 we know ,Cose theta =1+cost Theta see that = 1+2 tan2 the to sort cost 2 theta =sec 2 theta cost theta + sectha=5 /7 than for questions anser is 250
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