plz help me questions 4
Attachments:
Answers
Answered by
0
in both use bracket a + b + C whole square
Answered by
1
hey !!!
By using (a + b+ c)² = a²+ b² + c² + 2ab+2bc +2ca we can solve that equation ..
let us see ...
(x+y+z)²+ (x-y-z)²
=> x²+y²+z²+2xy+2yz+2xz +x²+ y² +z² -2xy+2yz-2xz
=] 2(x²+y²+z²+2yz)
=> 2{(y²+z²)²+x²}
hope it helps !!
#Rajukumar111
By using (a + b+ c)² = a²+ b² + c² + 2ab+2bc +2ca we can solve that equation ..
let us see ...
(x+y+z)²+ (x-y-z)²
=> x²+y²+z²+2xy+2yz+2xz +x²+ y² +z² -2xy+2yz-2xz
=] 2(x²+y²+z²+2yz)
=> 2{(y²+z²)²+x²}
hope it helps !!
#Rajukumar111
naira26:
thanxx rajkumar111
Similar questions