Question

plz help me. solve by using linear equation in one variable.
Frnds plz rply if u know the ans​

Answer 1

$Let \: units \: place \: digit = x$

$Ten's \: place \:digit = (x+1)$

$\blue { Original \: number } = 10(x+1)+x \\= 10x + 10 + x \\= 11x + 10 \: ---(1)$

$If \: Reversing \: the \: digits \: then \: the \\new \: number \: so \: formed = 10x + (x+1) \\= 11x + 1\: --(2)$

/* According to the problem given */

$(1) + (2) = 33$

$\implies 11x + 10 + 11x + 1 = 33$

$\implies 22x + 11= 33$

$\implies 22x = 33 - 11$

$\implies 22x = 22$

/* Dividing bothsides by 22 , we get */

$\implies x = 1$

/* Put x = 1 in equation (1), we get */

$\blue { Original \: number } = 11\times 1 + 10 \\= 11 + 10 \\= 21$

Therefore.,

$\red { Required \: number } \green { = 21 }$

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