Math, asked by Sheereen1, 1 year ago

plz help me solve these questions

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Answered by KEJAL
1
(III)   x = 3-2√2
       x² = (3-2√2)²
     ∴x² = 3²- 2×3×2√2 +(2√2)²
       x² = 9 -12√2+8
       x²= 17 -12√2
    ∵ x²+1/x² = 17-12√2 +1 / 17-12√2
                   = 18-12√2 / 17-12√2
                   = (18-12√2)(17+12√2) / (17-12√2)(17+12√2)
                   = 18(17+12√2)-12√2(17+12√2) / (17)²-(12√2)²
                   = 306+216√2-204√2-288 / 289-288
                   = 306-288+12√2 / 1
                   = 18 + 12√2
∴ the answer is 18+12√2

SORRY I DON`T KNOW THE ANSWER OF (II).

BUT I HOPE THE (III) IS HELPFUL TO YOU......

THANK YOU!!!!

Sheereen1: in 2nd it is x=
KEJAL: okay
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