plz help me solve these questions
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(III) x = 3-2√2
x² = (3-2√2)²
∴x² = 3²- 2×3×2√2 +(2√2)²
x² = 9 -12√2+8
x²= 17 -12√2
∵ x²+1/x² = 17-12√2 +1 / 17-12√2
= 18-12√2 / 17-12√2
= (18-12√2)(17+12√2) / (17-12√2)(17+12√2)
= 18(17+12√2)-12√2(17+12√2) / (17)²-(12√2)²
= 306+216√2-204√2-288 / 289-288
= 306-288+12√2 / 1
= 18 + 12√2
∴ the answer is 18+12√2
SORRY I DON`T KNOW THE ANSWER OF (II).
BUT I HOPE THE (III) IS HELPFUL TO YOU......
THANK YOU!!!!
x² = (3-2√2)²
∴x² = 3²- 2×3×2√2 +(2√2)²
x² = 9 -12√2+8
x²= 17 -12√2
∵ x²+1/x² = 17-12√2 +1 / 17-12√2
= 18-12√2 / 17-12√2
= (18-12√2)(17+12√2) / (17-12√2)(17+12√2)
= 18(17+12√2)-12√2(17+12√2) / (17)²-(12√2)²
= 306+216√2-204√2-288 / 289-288
= 306-288+12√2 / 1
= 18 + 12√2
∴ the answer is 18+12√2
SORRY I DON`T KNOW THE ANSWER OF (II).
BUT I HOPE THE (III) IS HELPFUL TO YOU......
THANK YOU!!!!
Sheereen1:
in 2nd it is x=
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