Question

plz help me solve this ....​

Answer 1

Answer:

construct normal lines from b and c and join it at f and g respectively

Step-by-step explanation:

since bf and cg are normal lines

so angle fbg=90° and angle gcf=90°

since,pq||rs

angle bgc=90°and angle bfc=90°

so all angles of bfcg are 90°

bfcg is a rectangle

so bf is parallel to cg

let mark the angles formed by bisecting for abc as angle 1 and the angles formed by bisecting for bcd as angle 2

so as bf||cg angle 1=angle 2(alternate interior angles)

also angle abf =angle 1 and angle gcd = angle 2 (law of reflection)

so angle abc=angle 1 +angle 1 =2angle 1

and

angle bcd=angle 2 +angle 2 =2 angle 2

but angle 1 =angle 2

2angle 1 =2 angle 2

angle abc =angle bcd

so ab ||cd

hence proved