Question

plz help me solve this

Answer 1

We know that Each Mg²⁺ ion has 12 Protons and 10 Electrons

As the Charge of Proton is Equal and Opposite to that of Electron

The Net Charge Remaining on Each Mg²⁺ ion is :

= (12 Protons - 10 Electrons) = 2 Protons Charge

We know that Charge of One Proton = 1.602 × 10⁻¹⁹ Coulombs

Net Charge Remaining on Each Mg²⁺ ion :

= 2 Protons = 2 × 1.602 × 10⁻¹⁹ = 3.204 × 10⁻¹⁹ C

We know that One Mole of Magnesium weighs 24 Grams

⇒ Two Moles of Magnesium weighs 48 grams

We know : One Mole of Magnesium Contains 6.023 × 10²³ Mg Atoms

⇒ Two Moles of Magnesium contains 12.046 × 10²³ Mg Atoms

⇒ 48 grams of Mg²⁺ Contains 12.046 × 10²³ Mg²⁺ Ions

We found that Each Mg²⁺ Ion has a Charge of 3.204 × 10⁻¹⁹ C

⇒ 12.046 × 10²³ Mg²⁺ Ions has (12.046 × 10²³ × 3.204 × 10⁻¹⁹)

⇒ 12.046 × 10²³ Mg²⁺ Ions has 3.6 × 10⁵ C

⇒ The Charge of 48 grams of Mg²⁺ is 3.6 × 10⁵ C

Option (3) is the Answer

Answer 2

Molar mass of Mg =24g/mol
Mass is given = 48g
Moles of magnesium = mass / molar mass = 48/24=2

In Mg^+2 there are 2 moles of electron
Im 2 moles Mg^+2 number of electron will be =2×2 =4moles of electron

Now

Moles of electron =Number of electron / Avagadro number

Number of electron = moles of electron × Avagadro number

Number of electron = 4 × 6.02×10^23

Now charge of total electron is =4 × 6.02 × 10^23 × 1.6×10^_19 (we know that charge of 1 electron is 1.6×10^_19).

Total charge =38.52 × 10^_19+23

Total charge = 38.52×10^4

Total charge =3.85×10^5C

___________________

Option 3 is correct

___________________