Plz help me solve this....Its urgent
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in Q.1
let 1.2727.. be x
so
1.2727=x
multiplying 100 on both the sides
127.2727=100x
subtract x from both the sides
127.2727-1.2727=99x
126=99x
x=126/99
in Q2
ye nahi aata yrrr kya kare
in Q3
1/√2
multiply and divide√2
(1×√2)/(√2×√2)
√2/2 is answer
in Q4
(1)2⅔×2⅓
=(2²×2¹)⅓
=(2³)⅓
answer is 2
in Q5
sorry Lekin ye wala bhi nahi aata
↓↓↓↓
inQ6
32^1/5
(2^5)^1/5
answer is 2
in Q7
32^2/5
(32×32)^1/5
(2^5×2^5)^1/5
(2^10)^1/5
2² or 4 is your answer
in Q8
2⅔×2^1/5
2^10/15×2^3/15
(2^10+2^3)^1/5
(2¹³)^1/5
answer is 2^13/15
Q9
Answer is c
Q10
answer is b,c,d
Q 11.
answer is a and c
let 1.2727.. be x
so
1.2727=x
multiplying 100 on both the sides
127.2727=100x
subtract x from both the sides
127.2727-1.2727=99x
126=99x
x=126/99
in Q2
ye nahi aata yrrr kya kare
in Q3
1/√2
multiply and divide√2
(1×√2)/(√2×√2)
√2/2 is answer
in Q4
(1)2⅔×2⅓
=(2²×2¹)⅓
=(2³)⅓
answer is 2
in Q5
sorry Lekin ye wala bhi nahi aata
↓↓↓↓
inQ6
32^1/5
(2^5)^1/5
answer is 2
in Q7
32^2/5
(32×32)^1/5
(2^5×2^5)^1/5
(2^10)^1/5
2² or 4 is your answer
in Q8
2⅔×2^1/5
2^10/15×2^3/15
(2^10+2^3)^1/5
(2¹³)^1/5
answer is 2^13/15
Q9
Answer is c
Q10
answer is b,c,d
Q 11.
answer is a and c
yashasvi019:
sorry @ginevra 2 Questions skip kiye hai
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