PLZ HELP ME SOLVE THIS QUESTION, I AM IN A HURRY , PLZ HELP ME
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i) EDF=32 ,
DEF=47 (alternate interior angles)
In triangle DEF ,
E+D+F=180
47+32+F=180
F=180-79
F=101
DFE=101
ii) BCD=90
BCF+FCD=BCD
47 +FCD=90
FCD=90 - 47
FCD=43
EDF=FBC=32 (alternate interior angles )
In triangle BCD ,
B+C+D=180
32+90+D=180
D=180-122
D=58
BDC=58
I HOPE IT HELPS YOU.......
Answered by
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Answer:
27 and 42 respectively.
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