Question

plz help me solve this question urgently

Answer 1

thus is solution of your question
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Answer 2

i) consider triangle ABC
PQ║BC (given)
∴AQ/AB= AP/AC---------1   (Basic Proportionality theorem)

consider triangle  ADC
PR║DC
∴AR/AD= AP/AC--------- 2     (Basic proportionality theorem)

 ∴ RHS of 1 and 2 are equal.
∴AQ/AB=AR/AD

ii)consider triangle ABC
PQ║BC (given)
∴BQ/AQ= PC/AP---------1   (Basic Proportionality theorem)

consider triangle  ADC
PR║DC
∴DR/AR= PC/AP--------- 2     (Basic proportionality theorem)

∴ RHS of 1 and 2 are equal.
∴BQ/AQ=DR/AR

HENCE Proved