Question

plz help me solving this problem​

Answer 1

Answer:

Step-by-step explanation:

Given;

let ABCD be the quadrilateral circumscribing the circle with centre O. the quadrilateral touches the circle at point P,Q,Rand S

To prove;

AB+CD=AD+BC

Proof;

From theorem 10.2, lengths of tangents drawn from external point are equal

Hence, AP=AS   .......(1)

BP=BQ       ...........(2)

CR=CQ      ............(3)

DR=DS       ............(4)

Adding equation (1)+(2)+(3)+(4)

AP+BP+CR+DR=AS+BQ+CQ+DS

(AP+BP) + (CR+DR)=(AS+DS) + (BQ+CQ)

AB+CD=AD=BC

Hence Proved