Question

plz help me this is 7th grade question ​

Answer 1

Answer =

∠ABC = ∠ACB = 50⁰

Explanation =

In triangle ABC

∠ABC = ∠ACB (Angle opposite to equal sides are equal)

therefore, let ∠ABC and ∠ACB = x

∠ABC + ∠ACB + ∠BAC = 180⁰

x + x + 80⁰ = 180⁰

2x + 80⁰ = 180⁰

2x = 180⁰ - 80⁰

2x = 100⁰

x = 100⁰/2

x = 50⁰

therefore, ∠ABC = ∠ACB = 50⁰

OR

In triangle ABC

∠BAC + ∠ACB = ∠ACD

80⁰ + ∠ACB = 130⁰

∠ACB = 130⁰ - 80⁰

∠ACB = 50⁰

∠ABC + ∠ACB + ∠BAC = 180⁰

∠ABC + 50⁰ + 80⁰ = 180⁰

∠ABC + 130⁰ = 180⁰

∠ABC = 180⁰ - 130⁰

∠ABC = 50⁰

Answer 2

Answer:

ACB = 50°

ABC = 50°

Yes, It is an isosceles triangle.

Step-by-step explanation:

ACB=180°-130°=50° ( Linear pair)

ABC=180°-(80°+50°) (Angle sum property)

=180°-130°

=50°

Yes , ABC and ACB are equal. So it is an isosceles triangle