Question

plz help me to answer this question..​

Answer 1

Answer:

${2}^{ - 2 log_{2}( \sqrt{2} ) } = {2}^{ - 2 log_{2}( {2}^{ \frac{1}{2} } ) } = {2}^{ - 2 \times \frac{1}{2} log_{2}(2) } = {2}^{ - 1} = \frac{1}{2} \\ because \: log_{a}(a) = 1$ and log a raise to n = ntimes loga