Math, asked by sunitagoyal1092, 19 days ago

plz help me to do this plz plz plz​

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Answered by a65139444
0

Answer:

From the given figure,

In triangles DAC and CBD, we have:

AD = BC

AC = BD

DC = DC

So, by SSS congruence rule

∆ADC ≅ ∆BCD

∴ By Congruent parts of congruent triangles we have:

∠CAD = ∠CBD

∠ADC = ∠BCD

∠ACD = ∠BDC

Hence, proved

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