plz help me to find this
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Step-by-step explanation:
⇒(x²)²-{(y+z)²}²
⇒Using a²-b²=(a+b)(a-b)
⇒{x²+(y+z)²}{x²-(y+z)²}
⇒Using (a+b)²=a²+2ab+b²
⇒(x²+y²+2yz+z²){x²-(y+z)²}
⇒Using a²-b²=(a+b)(a-b)
⇒(x²+y²+2yz+z²) (x+y+z) {x-(y+z)}
Final answer = (x²+y²+2yz+z²) (x+y+z) (x-y-z)
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