Question

plz help me to solve......​

Answer 1

$\pink{given : } \\ \\ mlk = 90 \\ \\ </p><p>\pink{To \: \: find : }raius \\ \\ angle \: \: k \: \: \: nd \: \: \: m \\ \\ \blue{solution : }</p><p>in \: \: triangle \: \: \: mlk \\ \\ {mk}^{2} = {ml}^{2} + {kl}^{2} </p><p> \\ \\ {12}^{2} = {ml}^{2} + {(6 \sqrt{3}) }^{2} \\ \\ 144 = {ml}^{2} + 108 \\ \\ 144 - 108 = {ml}^{2} \\ \\ 36 = {ml}^{2} \\ \\ 6 = ml \\ \\ \pink{radius} = 6 \\ \\ now \\ \\ let \: \: \: m = \alpha \\ k = \beta \\ \\ \sin( \alpha ) = \frac{6 \sqrt{3} }{12} = \frac{ \sqrt{3} }{2} </p><p> \\ \\ \sin( \alpha ) = \sin(60) \\ \\ \alpha = 60 \\ \\ m = 60 \\ \\ \sin( \beta ) = \frac{1}{2} \\ \\ \sin( \beta ) = \sin(30) \\ \\ \beta = 30 \\ \\ k = 30 \\ \\ \pink{pleas \: \: \: mrk \: \: \: me \: \: as \: \: \: brainlist}</p><p>$

Answer 2

Answer:

Radius=ML

there fore

(ML) ^2+(LK) ^2=(MK) ^2....... pythagoras theorem

=(ML) ^2+(6√3) ^2=(12) ^2

=(ML)^2+36×3=144

=(ML) ^2+108=144

=(ML)^2=36

=ML=√36

ML =6

RADIUS IS ML WHICH IS 6 UNITS.

SINCE SIDE ML=1/2 HYPOTENUSE MK

BY 30°-60°-90° THEOREM

ANGLE M =30° and ANGLE K=60°