Question

plz help....me to solve these​

Answer 1

Answer:

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Answer 2

$\frac{2}{( \sqrt{2} + \sqrt{3} ) - \sqrt{5} } \times \frac{( \sqrt{2} + \sqrt{3}) - \sqrt{5} }{( \sqrt{2} + \sqrt{3}) - \sqrt{5} } \\ \frac{2( \sqrt{2} + \sqrt{3} - \sqrt{5} ) }{( { \sqrt{2} + \sqrt{3}) }^{2} - { (\sqrt{5} )}^{2} } \\ \frac{2( \sqrt{2} + \sqrt{3} - \sqrt{5} )}{2 + 2 \sqrt{6} + 3 - 5 } \\ \frac{2( \sqrt{2} + \sqrt{3} - \sqrt{5} ) }{2 \sqrt{6} } \\ \frac{ \sqrt{2} + \sqrt{3} - \sqrt{5} }{ \sqrt{6} } \\ now \: to \: rationalize \: \sqrt{6} \\ \frac{ \sqrt{2} + \sqrt{3} - \sqrt{5} }{ \sqrt{6} } \times \frac{ \sqrt{6} }{ \sqrt{6} } \\ \frac{ \sqrt{6} ( \sqrt{2} + \sqrt{3} - \sqrt{5} ) }{6}$

Hence the denominator is rationalised...

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