Question

plz help me to solve this

Answer 1

Solution: LHS= cos(90⁰-A)sin(90⁰-A)/tan(90°-A)
                      =(sinA cosA)/(cotA)                 (sin(90-A)=cosA similarly other)
                      =(sinA cosA)/(cosA/sinA)         (cotA=cosA/sinA)
                       cosA, cosA cancelled out
                      =Sin²A
                      =1-cos²A = RHS
                 LHS=RHS
 mARK AS BRAINLIEST IF POSSIBLE

Answer 2

solution using trignometric ratios and trignometric identities