Math, asked by Vizag, 1 year ago

Plz help me to solve this

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Answered by kmodi2222
2
internal diameter is 50 cm
length of pipe h is 140 cm
internal radius r2is 50/2=25cm
thickness =2cm
outer radius r1 =25+2=27cm
volume = 22/7×140{(27)^2-(25)^2}
=22/7×140×(729-625)
=22×20×104
=45760 cm^3
Answered by BloomingBud
5

Given

internal diameter = 50 cm

length of pipe (height) = 140 cm

the pipe is made up of 2 cm thick iron

so,

the external diameter = 50 + 2 + 2 = 54 cm

radius = diameter ÷ 2

Internal radius (of internal diameter) = 50 ÷ 2

= 25cm.

External radius (of external diameter) = 54 ÷ 2

= 27 cm.

Volume of whole pipe (with the volume of iron) of  external radius =

=  = \pi {r}^{2} h \\ \\ = \frac{22}{7} \times( {27})^{2} \times 140 \\ \\ = 22 \times 27 \times 27\times 20 \\ \\ = {320760}cm^{3}

volume of empty space inside the pipe

of internal radius

=  = \pi {r}^{2} h \\ \\ = \frac{22}{7} \times ( {25})^{2} \times 140 \\ \\ = 22 \times 25 \times 25 \times 20 \\ \\ = {275000}cm^{3}

now volume of iron in it

= volume of whole pipe - volume of empty space inside

= 320760 - 275000

= 45760

\bf so \\ the \: volume \: of \: iron \: is \:{45760}cm^{3}


Vizag: Thanks mamtamajhi for helping but I need to know the answers of 2 questions more so can u help me with that, I've posted them. I need to know the answer of the 7 and the 10th one. Plz try them.
Vizag: I've posted them 11hrs ago.
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