Question

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Answer 1

Answer:

hope this will help u bro

brofist

17)

angle ACB equal to 180 - ( 30+45) = 105° (angle sum property of triangle)

angleACD equal to 180 - 105 = 75°{linear angle}

angle x is equal to angle 75 + 20 = 95°{exterior angle property of triangle}

18)

angle EGB = angle GHD = 35°{corresponding angle of transversal}

angle GHD = angle QHP = 35° {opposite angles}

angle PQH = 55°{angle sum property of triangle}

Answer 2

Answer:

x = 95°

∠PQH =  55°

Step-by-step explanation:

17. ∠ACB = ∠CAB + ∠ABC  [EAP of a triangle]

==> ∠ACB = 30° + 45°

==> ∠ACB = 75°

x = ∠ACB + ∠MDC   [EAP of a triangle]

==> x = 75° +20°

==> x = 95°

18. ∠AGH = ∠EGB = 35°       [VOA]

==> ∠AGH = ∠QHP = 35°       [Corresponding angles]

∠QHP + ∠HPQ + ∠PQH = 180°       [ASP of a triangle]

==> ∠PQH = 180° - (35° + 90°)

==> ∠PQH =  55°