Plz help me to solve this math
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lim x→ π/2 2x-π/cosx
Put x=π/2 , we get 0/0 form.
Simply we can apply L - Hospital rule here .
thus lim x→π/2 d/dx(2x) - d/dx(π)/d/dx(cosx)
=> lim x→π/2 -2/sinx
now we can put x =π/2
=> -2/sinπ/2 = -2
Thus :::
lim x→ π/2 2x-π/cosx = -2
Put x=π/2 , we get 0/0 form.
Simply we can apply L - Hospital rule here .
thus lim x→π/2 d/dx(2x) - d/dx(π)/d/dx(cosx)
=> lim x→π/2 -2/sinx
now we can put x =π/2
=> -2/sinπ/2 = -2
Thus :::
lim x→ π/2 2x-π/cosx = -2
Anonymous:
:-)
nice sir ji
bro !! i m in 12th class
:)
sorry
misunderstanding
no problem .
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