Question

plz help me to solve this
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Answer 1

let common ratio be x
sides are 12x and 5x
now by Pythagoras theorem
${(12x)}^{2} + {(5x)}^{2} = {52}^{2} \\ 144 {x}^{2} + 25 {x}^{2} = 2704 \\ 169 {x}^{2} = 2704 \\ {x}^{2} = 16 \\ x = 4$
hence sides are 12x=48
5x=20

Answer 2

Let the ratio be x
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