plz help me to solve this question and right answer will be marked as brainist
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Answered by
1
We assume he has Rs X
1/10 of X = X/10 donated to school
1/6 of X = X/6 donated to church
So, remaining =
X - (X/10 + X/6 )
= X - (16X/60 )
= 44X/60 was distributed among 3 chidren
So, each gets (44X/60) ÷3
=> 11X/45 = 50000
=> 11X = (50,000 * 45 )
=> X = 20,4545.45…
He originally had Rs 20,4545 ( approx)
Sheony:
wrong u idiot
You’re such a beautiful, intelligent, wonderful person. Oh I'm sorry, I thought we were having a lying competition.
wtf
If I'm wrong, can you please tell the correct answer? ^-^
Answered by
0
Let the money of man be x rupees
Money donated to school=x/10
Remaining money=9x/10
Money donated to church=9x/10*(1/6)=3x/20
Remaining money=17x/20
Money each child recieves=17x/20*(1/3)=17x/60
17x/60=50000
then, x=176470
Money donated to school=x/10
Remaining money=9x/10
Money donated to church=9x/10*(1/6)=3x/20
Remaining money=17x/20
Money each child recieves=17x/20*(1/3)=17x/60
17x/60=50000
then, x=176470
9x/10-3x/20
divided by 3
not x - 3x/20
get it now?
so x/4 = 50000
x = 2,00,000
yaa understood y mistake!
that's the answer
look at the number of comments lol
ikr
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