Question

plz help me trigonometry ​

Answer 1

Hey Pretty Stranger!

Given :

$\dfrac{5 \cos {}^{2} {60}^{ \circ} + 4 \sec ^{2} {30}^{ \circ} - \tan ^{2} {45}^{ \circ} }{ \sin ^{2} {30}^{ \circ} + \cos ^{2}30 ^{ \circ} }$

We know that :

$\bullet \sf \: \cos{60}^{ \circ} = \dfrac{1}{2}$

$\bullet \sf \: \tan{45}^{ \circ} = 1$

$\bullet \sf \: \sec{30}^{ \circ} = \dfrac{2}{ \sqrt{3} }$

So,

→ 5 × (½)² + 4 × (2/√3)² - (1)²/ 1

→ 5/4 + 4(4/3) - 1

→ 5/4 + 16/3 - 1

→ 15 + 64 - 12/12

→ 79 - 12/12

→ 67/12