Question

Plz help me with 42nd q......​

Answer 1

Answer: 741

Hope it helps!!!!!

Answer 2

Step-by-step explanation:

So here the series of two digit numbers which are divisible by 7 has to start with

14,21,28......91,98

Now according to the question we need a series which when divided by 7 leaves 1 as remainder

So the new desired series is

15,23,29.....92,99

Here a=15,l=98,d=7

Now find "n"

n=(l-a/d)+1

=(99-15)7

=(84)/7

=12+1

=13

Now find An

Sn=n/2[a+l]

=13/2[15+99]

=13/2[114]

=13[57]

=741