Question

PLZ HELP ME WITH QUESTION​

Answer 1

I'll be solving it on a paper as it requires a diagram for better understanding

Answer 2

$\huge{\bold{ \red{\underline{\mathcal{Hey!!! \: Mate}}}}}$

$\huge{\boxed{\bold{\mathbb{\blue{Answer}}}}}$

$\sin \theta = \frac{p}{q} = \frac{perpendicular }{hypotenuse} \\ it \: means \: perpendicular = p \: and \\ \: hypotenuse = q \\ \\ according \:to \: pythagorus \: theorem \\ {(hypotenuse)}^{2} = {(base)}^{2} + \\ {(perpendicular)}^{2} \\ {(base)}^{2} = {q}^{2} - {p}^{2} \\ cos \theta = \frac{base}{hypotenuse} = \frac{{q}^{2} - {p}^{2}}{q} \\ \\ cos \theta + sin \theta = \frac{{q}^{2} - {p}^{2}}{q} + \frac{p}{q} \\ \bold{ = \frac{ {q}^{2} - {p}^{2} + p}{q} }$