Question

plz help me with these ans​

Answer 1

$\mathcal{\gray{\underbrace{\blue{GIVEN:-}}}}$

In ∆ABC,

• D is the midpoint of ‘AB’ .

• E is the midpoint of ‘AC’ .

$\mathcal{\gray{\underbrace{\blue{TO\: FIND:-}}}}$

1. DE, if BC = 6cm .
2. ⟨ADE, if ⟨DBC = 140° .

$\mathcal{\gray{\underbrace{\blue{CALCULATION:-}}}}$

⚡ Using mid point theorem, A line segment joining the mid points of the two sides of the triangle, is equal to half the length of the third side .

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[1]

• D and E are the mid points .

Hence,

$\rm{\green{DE\:=\:\dfrac{1}{2}\:BC\:}}$

$\rm{\implies\:DE\:=\:\dfrac{1}{2}\times{6}\:}$

$\rm{\boxed{\purple{\implies\:DE\:=\:3cm\:}}}$

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[2] Here, According to theorem

• DE ll BC .

⚡ DE ll BC and AB is the intersection line .

Hence,

$\rm{\green{\angle{DBC}\:=\:\angle{ADE}\:}}$

$\rm{\boxed{\purple{\implies\:\angle{ADE}\:=\:140^{\degree}\:}}}$

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