Question

plz help me with this​

Answer 1

QUESTION:

Leela tells her daughter " seven years ago, I was seven times as old were you then . Also , three years from now , I shall be three times as old as you will be "

transform the given situation to form a pair of linear equations.

SOLUTION:

Let,

present age of Leela = x   years

and,

present age of her daughter = y  years

then,

age of Leela 7 years ago = x - 7      years

and, age of her daughter 7 years ago = y - 7   years

hence, according to the question

x - 7 = 7 ( y - 7 )

x - 7 = 7 y - 49

x - 7 - 7y + 49 = 0

x - 7 y + 42 = 0  -------------equation (1)

ALSO,

age of Leela three years later = x + 3    years

and, age of her daughter three years later = y + 3   years

again , as per question

x + 3 = 3 ( y + 3 )

x + 3 = 3 y + 9

x + 3 - 3 y - 9 = 0

x - 3 y - 6 = 0    ----------equation (2)

equation (1) and equation (2) are the required equations .

Answer 2

Answer:

Leeta's Age = 42

Daughter's Age = 12

Step-by-step explanation:

Let Leeta's present age be "x" and

Her daughter's age be "y".

According to the Q,

>> (x - 7) = 7(y - 7) -----(1)

>> (x + 3) = 3(y + 3) -----(2)

(1) => x - 7 = 7y - 49

>> x - 7y = -49 + 7

>> x - 7y = -42 -----(3)

(2) => x + 3 = 3y + 9

>> x - 3y = 9 - 3

>> x - 3y = 6 -----(4)

(4) - (3) =>

>> -3y + 7y = 6 + 42

>> 4y = 48

>> y = 48/4

>> y = 12

Substitute in -----(4)

>> x - 3 * 12 = 6

>> x - 36 = 6

>> x = 6 + 36

>> x = 42

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